Can’t use liquify within a photoshop action??

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Posted By
Marvinzzz
Mar 13, 2009
Views
635
Replies
4
Status
Closed
Hey guys,
Using CS3.
Made quite a long action with around 5 or so liquify distortions. When I got to run the action, it loads the liquify screen but then just stops and waits until I manually do some work and press enter or cancel. Pressing cancel brings me back to the canvas and the action stops.

Is there anyway I can force or otherwise PS to remember what I did during my edits from the liquified screen? Is this what the ‘save mesh’ command is for within the liquify tool? Am I doing something stupid? Please help as I really need to get liquifying recorded!
Thanks,
marv.
Related Tags
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PeterK.
Mar 13, 2009
Yes, save mesh will remember the distortions you made. The canvas size must be the same size in order for it to make the same distortion, although the resolution can be different. In other words, you could liquify on a low resolution version of your image, save the mesh, then load that mesh on a high resolution version of that same image or image of identical size.
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Marvinzzz
Mar 13, 2009
Thanks a lot PeterK. Sounds like quite a bit of work to get the mesh the same size :/ Do you have a link which explains saving & reusing meshes per chance? I couldn’t much about it on G.
M.
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Marvinzzz
Mar 13, 2009
Also Peter, do you know if the action can automatically load, execute and then return the result to the canvas? I don’t want to turn into a complete monkey!
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PeterK.
Mar 13, 2009
I think you misunderstood me. You can use the mesh on images of the same size but different resolutions, but you don’t have to if you don’t want to. Simply do your distortions, save the mesh, then load it for any image of the same size and all your distortions will be applied. Note that if you go into and out of liquify, the mesh will not remember the distortions you made in previous liquify adjustments. Any mesh you save will only remember the distortions you applied within that current instance of the filter.
I don’t know how liquify may interact with an action, so you’ll have to test that yourself.

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